lyf3312的专栏

利用开源前端框架layUI 实现省市县的三级动态联动，下载既可用

spring data Neo4j 整合demo,基本整合案例，详细细节参考https://docs.spring.io/spring-data/neo4j/docs/5.1.3.RELEASE/reference/html

对destoon系统做的一些二次开发，和文档

软件设计模式及一些资源，headfirst，敏捷开发pdf，和融合各设计模式的一些类图，java代码实现payroll，

常用算法分析ppt

非常好用的时间插件，时间可以设置是否精确到时分秒，

百度开放云直播、点播数据统计代码，

百度开放云点播api实例，php的VOD api

百度开放云直播lss 的SDK 实例，php源码。

matlab ppt及文档 教程，新手入门的绝佳书。

#include"stdio.h" #include"stdlib.h" #define YEAR 23 typedef struct{ int year; char name[24]; char team[30]; char finishschool[50]; }PLAYERINF; extern void display(PLAYERINF s[],int n), search(PLAYERINF s[]); void main() { PLAYERINF s[YEAR]={{1990,"柯曼","网队","syracuse"},{1991,"约翰逊","黄蜂","Nevada-las Vegas"}, {1992,"奥尼尔","魔术","Louisiana State"},{1993,"韦伯","魔术","Michigan"},{1994,"罗宾逊","雄鹿","Purdue"}, {1995,"史密斯","勇士","Maryland"},{1996,"艾弗森","76人","Georgetown"},{1997,"邓肯","马刺","Wake Forest"}, {1998,"欧罗伍坎迪","快艇","Brunel"},{1999,"布兰德","公牛","Duke"},{2000,"马丁","网队","Cincinnati"}, {2001,"夸梅-布朗","奇才","Glynn Academy"},{2002,"姚明","火箭","Shanghai"},{2003,"勒布朗-詹姆斯","骑士","St.Mary's HS"}, {2004,"德怀特-霍华德","魔术","Christian Academy"},{2005,"安德鲁-博格特","猛龙","Utah"},{2006,"安德烈-巴格纳尼","欧洲","不详"}, {2007,"格雷格-奥登","开拓者","Ohio State"},{2008,"德里克-罗斯","公牛","Memphis"},{2009,"格里芬","快船","Oklahoma"}, {2010,"约翰-沃尔","奇才","Country"},{2011,"凯瑞-欧文","骑士","Dunk Country"},{2012,"安东尼","黄蜂","肯塔基大学"}}; int ch; printf("\t\t\t\t功能菜单\n"); printf("===========================================================================\n"); printf("1.显示历届状元秀名单\n"); printf("2.按年份查找状元秀信息\n"); printf("0.退出\n"); scanf("%d",&ch); while(ch!=0) { switch(ch) { case 1: display(s,YEAR);break; case 2: search(s);break; default: printf("您输入错误，请重新输入！\n");break; } system("pause"); system("cls"); printf("功能菜单\n"); printf("================================================================================\n"); printf("1.显示历届状元秀名单\n"); printf("2.按年份查找状元秀信息\n"); printf("0.退出\n"); scanf("%d",&ch); } } void search(PLAYREINF s[]) { int k,number=0; PLAYREINT s1[1]; printf("请输入年份:\n"); scanf("%d",&number); for(k=0;k<YEAR;k++) { s1[0]=s[k]; display(s1,1) break; } if(k>YEAR) printf("您输入的年份有误，请重新输入一个在1990到2012之间的年份"); void display(PLAYERINF s[],int n) { int k; printf("=======================================历届状元秀名单=====================================\n"); printf("年份 姓名 所在球队 毕业学校\n"); printf("-------------------------------------------------------------------------------------------\n"); for(k=0;k<n;k++) { printf("%4d\t%-10s\ts\ts\n",s[k].year,s[k].name,s[k].team,s[k].finishschool); printf("=============================================================================\n"); } }

关于c语言中不等式求解代#include"stdio.h" #include"math.h" main() { double a,b,c,d; double x1,x2; printf("请将不等式化为一般形式ax^2+bx+c>0后，依次输入a b c：\n"); scanf(" ",&a,&b,&c); if(a==0) printf("不等式形式非法，a不能为0\n"); if(a>0) { d=b*b-4*a*c; if(d>0) { x1=(-b-sqrt(d))/(2*a); x2=(-b+sqrt(d))/(2*a); printf("原不等式的解集为:{x|x<%.2f,或x>%.2f}\n",x1<x2?x1:x2,x1>x2,x1:x2); } if(d==0) { x1=(-b+sqrt(d))/(2*a); printf("原不等式的解集为:{x|x!=%.2f}\n",x1); } if(d<0) printf("原不等式的解集为R\n"); } if(a<0) { d=b*b-4*a*c; if(d>0) { x1=(-b+sqrt(d))/(2*a); x2=(-b-sqrt(d))/(2*a); printf("原不等式的解集为：{x|%.2f<x<%.2f\n",x1<x2?x1:x2,x1>x2?x1:x2); } if(d<=0) printf("原不等式的解集为空集\n"); } }码