思源912的博客

竞赛题目#include <cstdio> #include <cstring> #include <ctype.h> #include <cstdlib> #include <cmath> #include <climits> #include <ctime> #include <iostream> #include <algorithm> #include <deque> #include <vector> #include <queue> #include <string> #include <map> #include <stack> #include <set> #include <numeric> #include <sstream> #include <iomanip> #include <limits> #define CLR(a) memset(a, 0, sizeof(a)) using namespace std; typedef long long ll; typedef long double ld; typedef unsigned long long ull; typedef pair <int, int> pii; typedef pair <ll, ll> pll; typedef pair<string, int> psi; typedef pair<string, string> pss; const double PI = 3.14159265358979323846264338327; const double E = exp(1); const double eps = 1e-6; const int INF = 0x3f3f3f3f; const int maxn = 1e6 + 5; const int MOD = 1e9 + 7; int main() { int n; cin >> n; vector <int> v; int num; for (int i = 0; i < n; i++) { scanf("%d", &num;); v.push_back(num); } cin >> n; for (int i = 0; i < n; i++) { scanf("%d", &num;); v.erase(v.begin() + num - 1); } vector <int>::iterator it; for (it = v.begin(); it != v.end(); it++) { if (it != v.begin()) printf(" "); cout << *it; } cout << endl; } --------------------- 作者：Dup4 来源：CSDN 原文：https://blog.csdn.net/dup4plz/article/details/79666083 版权声明：本文为博主原创文章，转载请附上博文链接！#include <cstdio> #include <cstring> #include <ctype.h> #include <cstdlib> #include <cmath> #include <climits> #include <ctime> #include <iostream> #include <algorithm> #include <deque> #include <vector> #include <queue> #include <string> #include <map> #include <stack> #include <set> #include <numeric> #include <sstream> #include <iomanip> #include <limits> #define CLR(a) memset(a, 0, sizeof(a)) using namespace std; typedef long long ll; typedef long double ld; typedef unsigned long long ull; typedef pair <int, int> pii; typedef pair <ll, ll> pll; typedef pair<string, int> psi; typedef pair<string, string> pss; const double PI = 3.14159265358979323846264338327; const double E = exp(1); const double eps = 1e-6; const int INF = 0x3f3f3f3f; const int maxn = 1e6 + 5; const int MOD = 1e9 + 7; int main() { int n; cin >> n; vector <int> v; int num; for (int i = 0; i < n; i++) { scanf("%d", &num;); v.push_back(num); } cin >> n; for (int i = 0; i < n; i++) { scanf("%d", &num;); v.erase(v.begin() + num - 1); } vector <int>::iterator it; for (it = v.begin(); it != v.end(); it++) { if (it != v.begin()) printf(" "); cout << *it; } cout << endl; } --------------------- 作者：Dup4 来源：CSDN 原文：https://blog.csdn.net/dup4plz/article/details/79666083 版权声明：本文为博主原创文章，转载请附上博文链接！